Nashville, Hancock County, Indiana | |
|---|---|
  Nashville  Nashville | |
| Coordinates: 39°55′42″N 85°39′34″W / 39.92833°N 85.65944°W | |
| Country | United States |
| State | Indiana |
| County | Hancock |
| Township | Brown |
| Elevation | 938 ft (286 m) |
| ZIP code | 46186 |
| FIPS code | 18-52045[1] |
| GNIS feature ID | 439942[2] |
Nashville is an unincorporated community in Brown Township, Hancock County, Indiana.
History
Geography
Nashville is located at 39°55′42″N 85°39′34″W / 39.92833°N 85.65944°W.
References
- ↑ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ↑ "Nashville, Hancock County, Indiana". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved October 17, 2009.
- ↑ Binford, John H. (1882). History of Hancock County, Indiana: From Its Earliest Settlement by the "pale Face," in 1818, Down to 1882. King & Binford. pp. 99.
Municipalities and communities of Hancock County, Indiana, United States | ||
|---|---|---|
| City |  Map of Indiana highlighting Hancock County | |
| Towns | ||
| Townships | ||
| CDPs | ||
| Other communities | ||
| Footnotes | ‡This populated place also has portions in an adjacent county or counties | |
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