Algebra/Arithmetic/Root Problems

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25^{\left({\frac {1}{2}}\right)}={\sqrt {25}}=

27^{\left({\frac {1}{3}}\right)}={\sqrt[{3}]{27}}=

(648+648)^{\frac {1}{4}}+8={\sqrt[{4}]{648+648}}+8=

512^{\frac {2}{3}}=({\sqrt[{3}]{512}})^{2}=

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